What is the general solution for -3=-2+tan(θ) ?

The general solution for -3=-2+tan(θ) is θ=(3pi)/4+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-3=-2+tan(θ)

- 3 = - 2 + tan (θ)

θ = \frac{3 π}{4} + πn

Degrees

θ = 13 5^{\circ} + 18 0^{\circ} n

Solution steps

- 3 = - 2 + tan (θ)

Switch sides

- 2 + tan (θ) = - 3

Move

2

to the right side

- 2 + tan (θ) = - 3

Add

2

to both sides

- 2 + tan (θ) + 2 = - 3 + 2

Simplify

tan (θ) = - 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

cos (7 x) (2 cos (x) + 1) = 0

- tan (x) + sec (x) = 1

tan (θ) = tan^{2} (θ)

15 tan (x) - 7 = 5 tan (x) - 3

sin (3 x + \frac{π}{18}) = 1

What is the general solution for -3=-2+tan(θ) ?
The general solution for -3=-2+tan(θ) is θ=(3pi)/4+pin