What is the general solution for sin(x)=sqrt(1) ?

The general solution for sin(x)=sqrt(1) is x= pi/2+2pin

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sin(x)=sqrt(1)

sin (x) = 1

x = \frac{π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = 1

Apply rule

1 = 1

sin (x) = 1

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

2 tan^{2} (θ) - tan (θ) = 0

3 sin (θ) + 2 = 0

7 cos (2 θ) = 7 cos (θ)

csc (4 x) = - 1

cos (θ) = \frac{m ^{2} - n ^{2}}{m ^{2} + n ^{2}}

What is the general solution for sin(x)=sqrt(1) ?
The general solution for sin(x)=sqrt(1) is x= pi/2+2pin