What is the general solution for sin(x)=1,-pi<= x<= 3pi ?

The general solution for sin(x)=1,-pi<= x<= 3pi is x= pi/2 ,x=(5pi)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)=1,-pi<= x<= 3pi

sin (x) = 1, - π \leq x \leq 3 π

x = \frac{π}{2}, x = \frac{5 π}{2}

Degrees

x = 9 0^{\circ}, x = 45 0^{\circ}

Solution steps

sin (x) = 1, - π \leq x \leq 3 π

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

Solutions for the range

- π \leq x \leq 3 π

x = \frac{π}{2}, x = \frac{5 π}{2}

15 sin (x) + 19 = 14 sin (x) + 18

3 + 3 sin (θ) = \frac{6}{3 - 2 sin ( θ )}

cos (x) = - 0.07

2 tan (θ) + 9 = 0

cos (x) = - 0.73

What is the general solution for sin(x)=1,-pi<= x<= 3pi ?
The general solution for sin(x)=1,-pi<= x<= 3pi is x= pi/2 ,x=(5pi)/2