What is the general solution for sin(x)-9=cos(x)-9 ?

The general solution for sin(x)-9=cos(x)-9 is x= pi/4+pin

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sin(x)-9=cos(x)-9

sin (x) - 9 = cos (x) - 9

x = \frac{π}{4} + πn

Degrees

x = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

sin (x) - 9 = cos (x) - 9

Subtract

cos (x) - 9

from both sides

sin (x) - cos (x) = 0

Rewrite using trig identities

sin (x) - cos (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{sin ( x ) - cos ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

\frac{sin ( x )}{cos ( x )} - 1 = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

tan (x) - 1 = 0

tan (x) - 1 = 0

Move

1

to the right side

tan (x) - 1 = 0

Add

1

to both sides

tan (x) - 1 + 1 = 0 + 1

Simplify

tan (x) = 1

tan (x) = 1

General solutions for

tan (x) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

7 sin (x) + 1 = 5 sin (x)

sec (x) + tan (x) = 1, (0, 2 π)

cos^{2} (θ) - cos (θ) - 20 = 0

100.0191 = 180 - arctan (\frac{3.9254}{0.6936 - x})

- 9 sin (x) = 0

What is the general solution for sin(x)-9=cos(x)-9 ?
The general solution for sin(x)-9=cos(x)-9 is x= pi/4+pin