What is the general solution for sin(x)=0.18,0<= x<2pi ?

The general solution for sin(x)=0.18,0<= x<2pi is x=0.18098…,x=pi-0.18098…

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sin(x)=0.18,0<= x<2pi

sin (x) = 0.18, 0 \leq x < 2 π

x = 0.18098 \dots, x = π - 0.18098 \dots

Degrees

x = 10.36975 \dots^{\circ}, x = 169.63024 \dots^{\circ}

Solution steps

sin (x) = 0.18, 0 \leq x < 2 π

Apply trig inverse properties

sin (x) = 0.18

General solutions for

sin (x) = 0.18

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (0.18) + 2 πn, x = π - arcsin (0.18) + 2 πn

x = arcsin (0.18) + 2 πn, x = π - arcsin (0.18) + 2 πn

Solutions for the range

0 \leq x < 2 π

x = 0.18098 \dots, x = π - 0.18098 \dots

3 cos (x) = sin (x)

sin^{2} (θ) - sin (θ) = cos^{2} (θ)

3 sin (x) = cos (x), - π \leq x \leq π

cos (x) = \frac{1999}{2000}

tan (13 5^{\circ} + x) = \frac{tan ( x ) - 1}{tan ( x ) + 1}

What is the general solution for sin(x)=0.18,0<= x<2pi ?
The general solution for sin(x)=0.18,0<= x<2pi is x=0.18098…,x=pi-0.18098…