What is the general solution for solvefor u,x=sin(u) ?

The general solution for solvefor u,x=sin(u) is u=arcsin(x)+2pin,u=pi+arcsin(-x)+2pin

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solvefor u,x=sin(u)

solve for

u, x = sin (u)

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

Solution steps

x = sin (u)

Switch sides

sin (u) = x

Apply trig inverse properties

sin (u) = x

General solutions for

sin (u) = x

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

u = arcsin (x) + 2 πn, u = π + arcsin (- x) + 2 πn

\frac{cos ( x )}{1 - cos ^{2} ( x )} = 23

- 3 sin (2 x) = 5 cos (2 x)

3 cot (x) - 1 = 0, 0 \leq x \leq 2 π

0.001 = \frac{sin ( θ ) \cdot 1 2 ^{2}}{9.81}

2 - 5 cos (x) = 0

What is the general solution for solvefor u,x=sin(u) ?
The general solution for solvefor u,x=sin(u) is u=arcsin(x)+2pin,u=pi+arcsin(-x)+2pin