What is the general solution for cot(x)+1=0,0<= x<= 2pi ?

The general solution for cot(x)+1=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4

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cot(x)+1=0,0<= x<= 2pi

cot (x) + 1 = 0, 0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

Degrees

x = 13 5^{\circ}, x = 31 5^{\circ}

Solution steps

cot (x) + 1 = 0, 0 \leq x \leq 2 π

Move

1

to the right side

cot (x) + 1 = 0

Subtract

1

from both sides

cot (x) + 1 - 1 = 0 - 1

Simplify

cot (x) = - 1

cot (x) = - 1

General solutions for

cot (x) = - 1

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}

- 4 cos (2 θ) + 7 cos (θ) + 4 = 9 cos (θ) + 7

a, sec (a) = csc (a)

9 - 2 cos (x) = 8 - 4 cos (x)

8 cos^{2} (x) + 2 sin (x) - 7 = 0

cos (θ) = sin (\frac{θ}{3} - 1 0^{\circ})

What is the general solution for cot(x)+1=0,0<= x<= 2pi ?
The general solution for cot(x)+1=0,0<= x<= 2pi is x=(3pi)/4 ,x=(7pi)/4