What is the general solution for 2cos(2x-pi/3)=1 ?

The general solution for 2cos(2x-pi/3)=1 is x= pi/3+pin,x=pin+pi

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2cos(2x-pi/3)=1

Solution

2 cos (2 x - \frac{π}{3}) = 1

Solution

x = \frac{π}{3} + πn, x = πn + π

Degrees

x = 6 0^{\circ} + 18 0^{\circ} n, x = 18 0^{\circ} + 18 0^{\circ} n

Solution steps

2 cos (2 x - \frac{π}{3}) = 1

Divide both sides by

2

2 cos (2 x - \frac{π}{3}) = 1

Divide both sides by

2

\frac{2 cos ( 2 x - \frac{π}{3} )}{2} = \frac{1}{2}

Simplify

cos (2 x - \frac{π}{3}) = \frac{1}{2}

cos (2 x - \frac{π}{3}) = \frac{1}{2}

General solutions for

cos (2 x - \frac{π}{3}) = \frac{1}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 x - \frac{π}{3} = \frac{π}{3} + 2 πn, 2 x - \frac{π}{3} = \frac{5 π}{3} + 2 πn

2 x - \frac{π}{3} = \frac{π}{3} + 2 πn, 2 x - \frac{π}{3} = \frac{5 π}{3} + 2 πn

Solve

2 x - \frac{π}{3} = \frac{π}{3} + 2 πn : x = \frac{π}{3} + πn

2 x - \frac{π}{3} = \frac{π}{3} + 2 πn

Move

\frac{π}{3}

to the right side

2 x - \frac{π}{3} = \frac{π}{3} + 2 πn

Add

\frac{π}{3}

to both sides

2 x - \frac{π}{3} + \frac{π}{3} = \frac{π}{3} + 2 πn + \frac{π}{3}

Simplify

2 x - \frac{π}{3} + \frac{π}{3} = \frac{π}{3} + 2 πn + \frac{π}{3}

Simplify

2 x - \frac{π}{3} + \frac{π}{3} : 2 x

2 x - \frac{π}{3} + \frac{π}{3}

Add similar elements:

- \frac{π}{3} + \frac{π}{3} = 0

= 2 x

Simplify

\frac{π}{3} + 2 πn + \frac{π}{3} : \frac{2 π}{3} + 2 πn

\frac{π}{3} + 2 πn + \frac{π}{3}

Group like terms

= \frac{π}{3} + \frac{π}{3} + 2 πn

Combine the fractions

\frac{π}{3} + \frac{π}{3} : \frac{2 π}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + π}{3}

Add similar elements:

π + π = 2 π

= \frac{2 π}{3}

= \frac{2 π}{3} + 2 πn

2 x = \frac{2 π}{3} + 2 πn

2 x = \frac{2 π}{3} + 2 πn

2 x = \frac{2 π}{3} + 2 πn

Divide both sides by

2

2 x = \frac{2 π}{3} + 2 πn

Divide both sides by

2

\frac{2 x}{2} = \frac{\frac{2 π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} = \frac{\frac{2 π}{3}}{2} + \frac{2 πn}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{\frac{2 π}{3}}{2} + \frac{2 πn}{2} : \frac{π}{3} + πn

\frac{\frac{2 π}{3}}{2} + \frac{2 πn}{2}

\frac{\frac{2 π}{3}}{2} = \frac{π}{3}

\frac{\frac{2 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{2 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{2 π}{6}

Cancel the common factor:

2

= \frac{π}{3}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

= \frac{π}{3} + πn

x = \frac{π}{3} + πn

x = \frac{π}{3} + πn

x = \frac{π}{3} + πn

Solve

2 x - \frac{π}{3} = \frac{5 π}{3} + 2 πn : x = πn + π

2 x - \frac{π}{3} = \frac{5 π}{3} + 2 πn

Move

\frac{π}{3}

to the right side

2 x - \frac{π}{3} = \frac{5 π}{3} + 2 πn

Add

\frac{π}{3}

to both sides

2 x - \frac{π}{3} + \frac{π}{3} = \frac{5 π}{3} + 2 πn + \frac{π}{3}

Simplify

2 x - \frac{π}{3} + \frac{π}{3} = \frac{5 π}{3} + 2 πn + \frac{π}{3}

Simplify

2 x - \frac{π}{3} + \frac{π}{3} : 2 x

2 x - \frac{π}{3} + \frac{π}{3}

Add similar elements:

- \frac{π}{3} + \frac{π}{3} = 0

= 2 x

Simplify

\frac{5 π}{3} + 2 πn + \frac{π}{3} : 2 πn + 2 π

\frac{5 π}{3} + 2 πn + \frac{π}{3}

Group like terms

= 2 πn + \frac{π}{3} + \frac{5 π}{3}

Combine the fractions

\frac{π}{3} + \frac{5 π}{3} : 2 π

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + 5 π}{3}

Add similar elements:

π + 5 π = 6 π

= \frac{6 π}{3}

Divide the numbers:

\frac{6}{3} = 2

= 2 π

= 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

2 x = 2 πn + 2 π

Divide both sides by

2

2 x = 2 πn + 2 π

Divide both sides by

2

\frac{2 x}{2} = \frac{2 πn}{2} + \frac{2 π}{2}

Simplify

x = πn + π

x = πn + π

x = \frac{π}{3} + πn, x = πn + π

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for 2cos(2x-pi/3)=1 ?
The general solution for 2cos(2x-pi/3)=1 is x= pi/3+pin,x=pin+pi