What is the general solution for sec(9x)=2 ?

The general solution for sec(9x)=2 is x= pi/(27)+(2pin)/9 ,x=(5pi}{27}+\frac{2pin)/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(9x)=2

Solution

sec (9 x) = 2

Solution

x = \frac{π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

Degrees

x = 6.66666 \dots^{\circ} + 4 0^{\circ} n, x = 33.33333 \dots^{\circ} + 4 0^{\circ} n

Solution steps

sec (9 x) = 2

General solutions for

sec (9 x) = 2

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

9 x = \frac{π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

9 x = \frac{π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

Solve

9 x = \frac{π}{3} + 2 πn : x = \frac{π}{27} + \frac{2 πn}{9}

9 x = \frac{π}{3} + 2 πn

Divide both sides by

9

9 x = \frac{π}{3} + 2 πn

Divide both sides by

9

\frac{9 x}{9} = \frac{\frac{π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} = \frac{\frac{π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} : x

\frac{9 x}{9}

Divide the numbers:

\frac{9}{9} = 1

= x

Simplify

\frac{\frac{π}{3}}{9} + \frac{2 πn}{9} : \frac{π}{27} + \frac{2 πn}{9}

\frac{\frac{π}{3}}{9} + \frac{2 πn}{9}

\frac{\frac{π}{3}}{9} = \frac{π}{27}

\frac{\frac{π}{3}}{9}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 9}

Multiply the numbers:

3 \cdot 9 = 27

= \frac{π}{27}

= \frac{π}{27} + \frac{2 πn}{9}

x = \frac{π}{27} + \frac{2 πn}{9}

x = \frac{π}{27} + \frac{2 πn}{9}

x = \frac{π}{27} + \frac{2 πn}{9}

Solve

9 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{27} + \frac{2 πn}{9}

9 x = \frac{5 π}{3} + 2 πn

Divide both sides by

9

9 x = \frac{5 π}{3} + 2 πn

Divide both sides by

9

\frac{9 x}{9} = \frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} = \frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

Simplify

\frac{9 x}{9} : x

\frac{9 x}{9}

Divide the numbers:

\frac{9}{9} = 1

= x

Simplify

\frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9} : \frac{5 π}{27} + \frac{2 πn}{9}

\frac{\frac{5 π}{3}}{9} + \frac{2 πn}{9}

\frac{\frac{5 π}{3}}{9} = \frac{5 π}{27}

\frac{\frac{5 π}{3}}{9}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{5 π}{3 \cdot 9}

Multiply the numbers:

3 \cdot 9 = 27

= \frac{5 π}{27}

= \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

Graph

Popular Examples

solvefor x,z=cos(xy)solve for

x, z = cos (x y)

cos^2(a)+2cos(a)=sin^2(a/2)-2

cos^{2} (a) + 2 cos (a) = sin^{2} (\frac{a}{2}) - 2

8tan^2(x)-8=0

8 tan^{2} (x) - 8 = 0

sin(x)+2cos^2(x)-2=0

sin (x) + 2 cos^{2} (x) - 2 = 0

4-sec^2(θ)=0

4 - sec^{2} (θ) = 0

Frequently Asked Questions (FAQ)

What is the general solution for sec(9x)=2 ?
The general solution for sec(9x)=2 is x= pi/(27)+(2pin)/9 ,x=(5pi}{27}+\frac{2pin)/9