What is the general solution for sin(x)=0.02 ?

The general solution for sin(x)=0.02 is x=0.02000…+2pin,x=pi-0.02000…+2pin

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sin(x)=0.02

sin (x) = 0.02

x = 0.02000 \dots + 2 πn, x = π - 0.02000 \dots + 2 πn

Degrees

x = 1.14599 \dots^{\circ} + 36 0^{\circ} n, x = 178.85400 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (x) = 0.02

Apply trig inverse properties

sin (x) = 0.02

General solutions for

sin (x) = 0.02

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (0.02) + 2 πn, x = π - arcsin (0.02) + 2 πn

x = arcsin (0.02) + 2 πn, x = π - arcsin (0.02) + 2 πn

Show solutions in decimal form

x = 0.02000 \dots + 2 πn, x = π - 0.02000 \dots + 2 πn

3 csc (x) - 2 = 4

sec (x) - sin (x) tan (x) = cos (x)

sec (x) - cos (x) = sin (x) tan (x)

csc (x) - sin (x) = cot (x) cos (x)

sec^{2} (x) + csc^{2} (x) = sec^{2} (x) csc^{2} (x)

What is the general solution for sin(x)=0.02 ?
The general solution for sin(x)=0.02 is x=0.02000…+2pin,x=pi-0.02000…+2pin