Is sec^2(x)(1-sin^2(x))=1 ?

The answer to whether sec^2(x)(1-sin^2(x))=1 is True

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prove sec^2(x)(1-sin^2(x))=1

prove

sec^{2} (x) (1 - sin^{2} (x)) = 1

True

Solution steps

sec^{2} (x) (1 - sin^{2} (x)) = 1

Manipulating left side

sec^{2} (x) (1 - sin^{2} (x))

Express with sin, cos

(1 - sin^{2} (x)) sec^{2} (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= (1 - sin^{2} (x)) (\frac{1}{cos ( x )})^{2}

Simplify

(1 - sin^{2} (x)) (\frac{1}{cos ( x )})^{2} : \frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

(1 - sin^{2} (x)) (\frac{1}{cos ( x )})^{2}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

= \frac{1}{cos ^{2} ( x )} (- sin^{2} (x) + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 - sin ^{2} ( x ) )}{cos ^{2} ( x )}

1 \cdot (1 - sin^{2} (x)) = 1 - sin^{2} (x)

1 \cdot (1 - sin^{2} (x))

Multiply:

1 \cdot (1 - sin^{2} (x)) = (1 - sin^{2} (x))

= (1 - sin^{2} (x))

Remove parentheses:

(a) = a

= 1 - sin^{2} (x)

= \frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

= \frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

= \frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

Rewrite using trig identities

\frac{1 - sin ^{2} ( x )}{cos ^{2} ( x )}

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= \frac{cos ^{2} ( x )}{cos ^{2} ( x )}

Apply rule

\frac{a}{a} = 1

= 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

sin (x) (1 + cot^{2} (x)) = csc (x)

sin^{4} (x) - cos^{4} (x) = 1 - 2 cos^{2} (x)

sec^{4} (x) - tan^{4} (x) = 1 + 2 tan^{2} (x)

1 + cot^{2} (x) = csc^{2} (x)

sin (- x) = - sin (x)

Is sec^2(x)(1-sin^2(x))=1 ?
The answer to whether sec^2(x)(1-sin^2(x))=1 is True