Is csc(x)(1-cos^2(x))=sin(x) ?

The answer to whether csc(x)(1-cos^2(x))=sin(x) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove csc(x)(1-cos^2(x))=sin(x)

prove

csc (x) (1 - cos^{2} (x)) = sin (x)

True

Solution steps

csc (x) (1 - cos^{2} (x)) = sin (x)

Manipulating left side

csc (x) (1 - cos^{2} (x))

Express with sin, cos

(1 - cos^{2} (x)) csc (x)

Use the basic trigonometric identity:

csc (x) = \frac{1}{sin ( x )}

= (1 - cos^{2} (x)) \frac{1}{sin ( x )}

Simplify

(1 - cos^{2} (x)) \frac{1}{sin ( x )} : \frac{1 - cos ^{2} ( x )}{sin ( x )}

(1 - cos^{2} (x)) \frac{1}{sin ( x )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 - cos ^{2} ( x ) )}{sin ( x )}

1 \cdot (1 - cos^{2} (x)) = 1 - cos^{2} (x)

1 \cdot (1 - cos^{2} (x))

Multiply:

1 \cdot (1 - cos^{2} (x)) = (1 - cos^{2} (x))

= (1 - cos^{2} (x))

Remove parentheses:

(a) = a

= 1 - cos^{2} (x)

= \frac{1 - cos ^{2} ( x )}{sin ( x )}

= \frac{1 - cos ^{2} ( x )}{sin ( x )}

= \frac{1 - cos ^{2} ( x )}{sin ( x )}

Rewrite using trig identities

\frac{1 - cos ^{2} ( x )}{sin ( x )}

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - cos^{2} (x) = sin^{2} (x)

= \frac{sin ^{2} ( x )}{sin ( x )}

Cancel the common factor:

sin (x)

= sin (x)

= sin (x)

We showed that the two sides could take the same form

\Rightarrow True

cos (x) = sin (x + \frac{π}{2})

sec (2 θ) = \frac{sec ^{2} ( θ )}{2 - sec ^{2} ( θ )}

\frac{cot ( x )}{tan ( x ) + cot ( x )} = cos^{2} (x)

tan (x) + cot (x) = \frac{2}{sin ( 2 x )}

\frac{cos ^{2} ( x )}{1 - sin ( x )} = 1 + sin (x)

Is csc(x)(1-cos^2(x))=sin(x) ?
The answer to whether csc(x)(1-cos^2(x))=sin(x) is True