Is sec(x)(1-sin^2(x))=cos(x) ?

The answer to whether sec(x)(1-sin^2(x))=cos(x) is True

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prove sec(x)(1-sin^2(x))=cos(x)

prove

sec (x) (1 - sin^{2} (x)) = cos (x)

True

Solution steps

sec (x) (1 - sin^{2} (x)) = cos (x)

Manipulating left side

sec (x) (1 - sin^{2} (x))

Express with sin, cos

(1 - sin^{2} (x)) sec (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= (1 - sin^{2} (x)) \frac{1}{cos ( x )}

Simplify

(1 - sin^{2} (x)) \frac{1}{cos ( x )} : \frac{1 - sin ^{2} ( x )}{cos ( x )}

(1 - sin^{2} (x)) \frac{1}{cos ( x )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 1 - sin ^{2} ( x ) )}{cos ( x )}

1 \cdot (1 - sin^{2} (x)) = 1 - sin^{2} (x)

1 \cdot (1 - sin^{2} (x))

Multiply:

1 \cdot (1 - sin^{2} (x)) = (1 - sin^{2} (x))

= (1 - sin^{2} (x))

Remove parentheses:

(a) = a

= 1 - sin^{2} (x)

= \frac{1 - sin ^{2} ( x )}{cos ( x )}

= \frac{1 - sin ^{2} ( x )}{cos ( x )}

= \frac{1 - sin ^{2} ( x )}{cos ( x )}

Rewrite using trig identities

\frac{1 - sin ^{2} ( x )}{cos ( x )}

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= \frac{cos ^{2} ( x )}{cos ( x )}

Cancel the common factor:

cos (x)

= cos (x)

= cos (x)

We showed that the two sides could take the same form

\Rightarrow True

sin (\frac{3 π}{2} - θ) = - cos (θ)

(1 - cos^{2} (θ)) (1 + cot^{2} (θ)) = 1

cot (x) sin (x) = cos (x)

tan (2 x) = \frac{2 tan ( x )}{1 - tan ^{2} ( x )}

(tan (θ) + cot (θ)) sin (θ) = sec (θ)

Is sec(x)(1-sin^2(x))=cos(x) ?
The answer to whether sec(x)(1-sin^2(x))=cos(x) is True