Is tan^2(θ)=sec^2(θ)-1 ?

The answer to whether tan^2(θ)=sec^2(θ)-1 is True

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prove tan^2(θ)=sec^2(θ)-1

prove

tan^{2} (θ) = sec^{2} (θ) - 1

True

Solution steps

tan^{2} (θ) = sec^{2} (θ) - 1

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

\Rightarrow True

(tan (x) + cot (x))^{2} = csc^{2} (x) sec^{2} (x)

(1 + sec (θ)) (1 - sec (θ)) = - tan^{2} (θ)

cos (x) = \frac{cot ( x )}{csc ( x )}

tan (\frac{θ}{2}) = \frac{sin ( θ )}{1 + cos ( θ )}

cot (t) cos (t) = csc (t) - sin (t)