Is sec(x)tan(x)cos(x)cot(x)=1 ?

The answer to whether sec(x)tan(x)cos(x)cot(x)=1 is True

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prove sec(x)tan(x)cos(x)cot(x)=1

prove

sec (x) tan (x) cos (x) cot (x) = 1

True

Solution steps

sec (x) tan (x) cos (x) cot (x) = 1

Manipulating left side

sec (x) tan (x) cos (x) cot (x)

Express with sin, cos

cos (x) cot (x) sec (x) tan (x)

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= cos (x) \frac{cos ( x )}{sin ( x )} sec (x) tan (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= cos (x) \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{cos ( x )} tan (x)

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= cos (x) \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

cos (x) \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )} = 1

cos (x) \frac{cos ( x )}{sin ( x )} \cdot \frac{1}{cos ( x )} \cdot \frac{sin ( x )}{cos ( x )}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{cos ( x ) \cdot 1 \cdot sin ( x ) cos ( x )}{sin ( x ) cos ( x ) cos ( x )}

Cancel the common factor:

cos (x)

= \frac{1 \cdot sin ( x ) cos ( x )}{sin ( x ) cos ( x )}

Cancel the common factor:

sin (x)

= \frac{1 \cdot cos ( x )}{cos ( x )}

Cancel the common factor:

cos (x)

= 1

= 1

= 1

We showed that the two sides could take the same form

\Rightarrow True

1 - sec (x) cos^{3} (x) = sin^{2} (x)

sin (2 x) (1 - cos (2 x)) = 4 sin^{3} (x) cos (x)

cot (θ) - 2 cot (2 θ) = tan (θ)

tan (3 π + θ) = tan (θ)

4 sin (- x) cos (- x) = - 2 sin (2 x)

Is sec(x)tan(x)cos(x)cot(x)=1 ?
The answer to whether sec(x)tan(x)cos(x)cot(x)=1 is True