Is (cos(θ)+sin(θ))/(cos(θ))=1+tan(θ) ?

The answer to whether (cos(θ)+sin(θ))/(cos(θ))=1+tan(θ) is True

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prove (cos(θ)+sin(θ))/(cos(θ))=1+tan(θ)

prove

\frac{cos ( θ ) + sin ( θ )}{cos ( θ )} = 1 + tan (θ)

True

Solution steps

\frac{cos ( θ ) + sin ( θ )}{cos ( θ )} = 1 + tan (θ)

Manipulating right side

1 + tan (θ)

Express with sin, cos

1 + tan (θ)

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= 1 + \frac{sin ( θ )}{cos ( θ )}

Simplify

1 + \frac{sin ( θ )}{cos ( θ )} : \frac{cos ( θ ) + sin ( θ )}{cos ( θ )}

1 + \frac{sin ( θ )}{cos ( θ )}

Convert element to fraction:

1 = \frac{1 cos ( θ )}{cos ( θ )}

= \frac{1 \cdot cos ( θ )}{cos ( θ )} + \frac{sin ( θ )}{cos ( θ )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot cos ( θ ) + sin ( θ )}{cos ( θ )}

Multiply:

1 \cdot cos (θ) = cos (θ)

= \frac{cos ( θ ) + sin ( θ )}{cos ( θ )}

= \frac{cos ( θ ) + sin ( θ )}{cos ( θ )}

= \frac{cos ( θ ) + sin ( θ )}{cos ( θ )}

We showed that the two sides could take the same form

\Rightarrow True

sin (2 x) = cot (x) (1 - cos (2 x))

\frac{cos ( θ )}{1 - sin ( θ )} - tan (θ) = sec (θ)

sec (x) csc (x) = \frac{sec ^{2} ( x )}{tan ( x )}

sin^{2} (θ) sec (θ) csc (θ) = tan (θ)

6 cot^{2} (y) (sec^{2} (y) - 1) = 6

Is (cos(θ)+sin(θ))/(cos(θ))=1+tan(θ) ?
The answer to whether (cos(θ)+sin(θ))/(cos(θ))=1+tan(θ) is True