Is sin(2a)=(2tan(a))/(1+tan^2(a)) ?

The answer to whether sin(2a)=(2tan(a))/(1+tan^2(a)) is True

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prove sin(2a)=(2tan(a))/(1+tan^2(a))

Solution

prove

sin (2 a) = \frac{2 tan ( a )}{1 + tan ^{2} ( a )}

Solution

True

Solution steps

sin (2 a) = \frac{2 tan ( a )}{1 + tan ^{2} ( a )}

Manipulating right side

\frac{2 tan ( a )}{1 + tan ^{2} ( a )}

Express with sin, cos

\frac{2 tan ( a )}{1 + tan ^{2} ( a )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{2 \cdot \frac{s i n ( a )}{c o s ( a )}}{1 + ( \frac{s i n ( a )}{c o s ( a )} ) ^{2}}

Simplify

\frac{2 \cdot \frac{s i n ( a )}{c o s ( a )}}{1 + ( \frac{s i n ( a )}{c o s ( a )} ) ^{2}} : \frac{2 sin ( a ) cos ( a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

\frac{2 \cdot \frac{s i n ( a )}{c o s ( a )}}{1 + ( \frac{s i n ( a )}{c o s ( a )} ) ^{2}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{2 \cdot \frac{s i n ( a )}{c o s ( a )}}{1 + \frac{s i n ^{2} ( a )}{c o s ^{2} ( a )}}

Multiply

2 \cdot \frac{sin ( a )}{cos ( a )} : \frac{2 sin ( a )}{cos ( a )}

2 \cdot \frac{sin ( a )}{cos ( a )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( a ) \cdot 2}{cos ( a )}

= \frac{\frac{2 s i n ( a )}{c o s ( a )}}{1 + \frac{s i n ^{2} ( a )}{c o s ^{2} ( a )}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{sin ( a ) \cdot 2}{cos ( a ) ( 1 + \frac{s i n ^{2} ( a )}{c o s ^{2} ( a )} )}

Join

1 + \frac{sin ^{2} ( a )}{cos ^{2} ( a )} : \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ^{2} ( a )}

1 + \frac{sin ^{2} ( a )}{cos ^{2} ( a )}

Convert element to fraction:

1 = \frac{1 cos ^{2} ( a )}{cos ^{2} ( a )}

= \frac{1 \cdot cos ^{2} ( a )}{cos ^{2} ( a )} + \frac{sin ^{2} ( a )}{cos ^{2} ( a )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot cos ^{2} ( a ) + sin ^{2} ( a )}{cos ^{2} ( a )}

Multiply:

1 \cdot cos^{2} (a) = cos^{2} (a)

= \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ^{2} ( a )}

= \frac{2 sin ( a )}{\frac{c o s ^{2} ( a ) + s i n ^{2} ( a )}{c o s ^{2} ( a )} cos ( a )}

Multiply

cos (a) \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ^{2} ( a )} : \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ( a )}

cos (a) \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ^{2} ( a )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( cos ^{2} ( a ) + sin ^{2} ( a ) ) cos ( a )}{cos ^{2} ( a )}

Cancel the common factor:

cos (a)

= \frac{cos ^{2} ( a ) + sin ^{2} ( a )}{cos ( a )}

= \frac{2 sin ( a )}{\frac{c o s ^{2} ( a ) + s i n ^{2} ( a )}{c o s ( a )}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{sin ( a ) \cdot 2 cos ( a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

= \frac{2 sin ( a ) cos ( a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

= \frac{2 cos ( a ) sin ( a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

Rewrite using trig identities

\frac{2 cos ( a ) sin ( a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= \frac{sin ( 2 a )}{cos ^{2} ( a ) + sin ^{2} ( a )}

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= \frac{sin ( 2 a )}{1}

Apply rule

\frac{a}{1} = a

= sin (2 a)

= sin (2 a)

We showed that the two sides could take the same form

\Rightarrow True

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Is sin(2a)=(2tan(a))/(1+tan^2(a)) ?
The answer to whether sin(2a)=(2tan(a))/(1+tan^2(a)) is True