Is sin(θ+pi/3)=sin(θ)+sin(pi/3) ?

The answer to whether sin(θ+pi/3)=sin(θ)+sin(pi/3) is False

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prove sin(θ+pi/3)=sin(θ)+sin(pi/3)

prove

sin (θ + \frac{π}{3}) = sin (θ) + sin (\frac{π}{3})

False

Solution steps

sin (θ + \frac{π}{3}) = sin (θ) + sin (\frac{π}{3})

Show that the two sides are not equal

For

sin (θ + \frac{π}{3}) = sin (θ) + sin (\frac{π}{3})

plug in

θ = 1

sin (1 + \frac{π}{3}) = 0.88865 \dots

sin (1 + \frac{π}{3})

Refine to a decimal form

= 0.88865 \dots

sin (1) + sin (\frac{π}{3}) = 1.70749 \dots

sin (1) + sin (\frac{π}{3})

Refine to a decimal form

= 1.70749 \dots

The two sides are not equal

\Rightarrow False

(4 sin (θ) - 4 cos (θ))^{2} = 16 - 16 sin (2 θ)

arcsec (x) = cos (x)

(csc (θ) - cot (θ)) (1 + sec (θ)) = tan (θ)

\frac{1 - sin ^{2} ( b )}{cos ( b )} = cos (b)

\frac{1 + csc ( θ )}{cot ( θ ) + cos ( θ )} = sec (θ)

Is sin(θ+pi/3)=sin(θ)+sin(pi/3) ?
The answer to whether sin(θ+pi/3)=sin(θ)+sin(pi/3) is False