Is 2sin(x)=(4cos(x)-1)/(tan(x)) ?

The answer to whether 2sin(x)=(4cos(x)-1)/(tan(x)) is False

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prove 2sin(x)=(4cos(x)-1)/(tan(x))

prove

2 sin (x) = \frac{4 cos ( x ) - 1}{tan ( x )}

False

Solution steps

2 sin (x) = \frac{4 cos ( x ) - 1}{tan ( x )}

Show that the two sides are not equal

For

2 sin (x) = \frac{4 cos ( x ) - 1}{tan ( x )}

plug in

x = 1

2 sin (1) = 1.68294 \dots

2 sin (1)

Refine to a decimal form

= 1.68294 \dots

\frac{4 cos ( 1 ) - 1}{tan ( 1 )} = 0.74560 \dots

\frac{4 cos ( 1 ) - 1}{tan ( 1 )}

Refine to a decimal form

= 0.74560 \dots

The two sides are not equal

\Rightarrow False

cos (8 x) = cos^{2} (4 x) - sin^{2} (4 x)

tan (\frac{π}{2} - x) cot (x) = csc^{2} (x) - 1

cot^{2} (θ) cos (2 θ) = cot^{2} (θ) - 2 cos^{2} (θ)

\frac{cot ^{2} ( x )}{cos ( x )} = cot (x) \cdot csc (x)

1 - tan (x) = \frac{cos ( x ) - sin ( x )}{cos ( x )}

Is 2sin(x)=(4cos(x)-1)/(tan(x)) ?
The answer to whether 2sin(x)=(4cos(x)-1)/(tan(x)) is False