Is csc(x)+sec(x)= 1/(sin(x)+cos(x)) ?

The answer to whether csc(x)+sec(x)= 1/(sin(x)+cos(x)) is False

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prove csc(x)+sec(x)= 1/(sin(x)+cos(x))

prove

csc (x) + sec (x) = \frac{1}{sin ( x ) + cos ( x )}

False

Solution steps

csc (x) + sec (x) = \frac{1}{sin ( x ) + cos ( x )}

Show that the two sides are not equal

For

csc (x) + sec (x) = \frac{1}{sin ( x ) + cos ( x )}

plug in

x = 1

csc (1) + sec (1) = 3.03921 \dots

csc (1) + sec (1)

Refine to a decimal form

= 3.03921 \dots

\frac{1}{sin ( 1 ) + cos ( 1 )} = 0.72370 \dots

\frac{1}{sin ( 1 ) + cos ( 1 )}

Refine to a decimal form

= 0.72370 \dots

The two sides are not equal

\Rightarrow False

\frac{2 cot ( x )}{sec ( x )} = 2 csc (x) - 2 sin (x)

cos (x) \cdot cot (x) + sin (x) = csc (x)

csc (t) - sin (t) = cot (t) cos (t)

\frac{sec ( x ) + 1}{sec ( x )} = 1 + cos (x)

\frac{cos ( A )}{1 + sin ( A )} + tan (A) = sec (A)

Is csc(x)+sec(x)= 1/(sin(x)+cos(x)) ?
The answer to whether csc(x)+sec(x)= 1/(sin(x)+cos(x)) is False