Is (sin(x)+cos(x))^2=1+2cos(x)sin(x) ?

The answer to whether (sin(x)+cos(x))^2=1+2cos(x)sin(x) is True

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prove (sin(x)+cos(x))^2=1+2cos(x)sin(x)

prove

(sin (x) + cos (x))^{2} = 1 + 2 cos (x) sin (x)

True

Solution steps

(sin (x) + cos (x))^{2} = 1 + 2 cos (x) sin (x)

Manipulating left side

(sin (x) + cos (x))^{2}

Expand

(cos (x) + sin (x))^{2} : cos^{2} (x) + 2 cos (x) sin (x) + sin^{2} (x)

(cos (x) + sin (x))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = cos (x), b = sin (x)

= cos^{2} (x) + 2 cos (x) sin (x) + sin^{2} (x)

= cos^{2} (x) + sin^{2} (x) + 2 cos (x) sin (x)

Rewrite using trig identities

cos^{2} (x) + sin^{2} (x) + 2 cos (x) sin (x)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= 1 + 2 cos (x) sin (x)

= 1 + 2 cos (x) sin (x)

We showed that the two sides could take the same form

\Rightarrow True

2 cos^{2} (x) = 1

\frac{cos ( a )}{sin ( a ) cot ( a )} = 1

2 (cos (3 θ) + 3 cos (θ)) = 8 cos^{3} (θ)

sin^{2} (\frac{t}{2}) = \frac{1 - cos ( t )}{2}

cos (θ) = (sec (θ) + tan (θ)) (1 - sin (θ))

Is (sin(x)+cos(x))^2=1+2cos(x)sin(x) ?
The answer to whether (sin(x)+cos(x))^2=1+2cos(x)sin(x) is True