Is 2cot(θ)cot(2θ)=cot^2(-1) ?

The answer to whether 2cot(θ)cot(2θ)=cot^2(-1) is False

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prove 2cot(θ)cot(2θ)=cot^2(-1)

prove

2 cot (θ) cot (2 θ) = cot^{2} (- 1)

False

Solution steps

2 cot (θ) cot (2 θ) = cot^{2} (- 1)

Show that the two sides are not equal

For

2 cot (θ) cot (2 θ) = cot^{2} (- 1)

plug in

θ = 1

2 cot (1) cot (2 \cdot 1) = - 0.58771 \dots

2 cot (1) cot (2 \cdot 1)

Refine to a decimal form

= - 0.58771 \dots

cot^{2} (- 1) = 0.41228 \dots

cot^{2} (- 1)

Refine to a decimal form

= 0.41228 \dots

The two sides are not equal

\Rightarrow False

\frac{cos ( x )}{sin ( x ) cot ^{2} ( x )} = tan (x)

(1 + sin (α)) (1 - sin (α)) = cos^{2} (α)

\frac{tan ( \frac{x}{2} )}{1 - cos ( x )} = \frac{1}{sin ( x )}

\frac{( tan ^{2} ( x ) )}{sec ( x ) + 1} = \frac{( 1 - cos ( x ) )}{cos ( x )}

1 + sin (x) = \frac{csc ( x ) + 1}{csc ( x )}

Is 2cot(θ)cot(2θ)=cot^2(-1) ?
The answer to whether 2cot(θ)cot(2θ)=cot^2(-1) is False