Is 1/(1-cos(x))+1/(1+cos(x))=csc(x^2) ?

The answer to whether 1/(1-cos(x))+1/(1+cos(x))=csc(x^2) is False

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prove 1/(1-cos(x))+1/(1+cos(x))=csc(x^2)

prove

\frac{1}{1 - cos ( x )} + \frac{1}{1 + cos ( x )} = csc (x^{2})

False

Solution steps

\frac{1}{1 - cos ( x )} + \frac{1}{1 + cos ( x )} = csc (x^{2})

Show that the two sides are not equal

For

\frac{1}{1 - cos ( x )} + \frac{1}{1 + cos ( x )} = csc (x^{2})

plug in

x = 1

\frac{1}{1 - cos ( 1 )} + \frac{1}{1 + cos ( 1 )} = 2.82456 \dots

\frac{1}{1 - cos ( 1 )} + \frac{1}{1 + cos ( 1 )}

Refine to a decimal form

= 2.82456 \dots

csc (1^{2}) = 1.18839 \dots

csc (1^{2})

Refine to a decimal form

= 1.18839 \dots

The two sides are not equal

\Rightarrow False

\frac{sin ( 2 x )}{2} = cos (x) sin (x)

\frac{1 + tan ^{2} ( x )}{cot ^{2} ( x ) + 1} = tan^{2} (x)

7 sec (y) cos (y) = 7

\frac{1 + cos ( 2 t )}{sin ( 2 t ) - cos ( t )} = \frac{2 cos ( t )}{2 sin ( t ) - 1}

(1 + sin (a)) (1 - sin (a)) = \frac{1}{sec ^{2} ( a )}

Is 1/(1-cos(x))+1/(1+cos(x))=csc(x^2) ?
The answer to whether 1/(1-cos(x))+1/(1+cos(x))=csc(x^2) is False