Is sec(x)cos(-x)-sin^2(x)=cos^2(x) ?

The answer to whether sec(x)cos(-x)-sin^2(x)=cos^2(x) is True

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prove sec(x)cos(-x)-sin^2(x)=cos^2(x)

prove

sec (x) cos (- x) - sin^{2} (x) = cos^{2} (x)

True

Solution steps

sec (x) cos (- x) - sin^{2} (x) = cos^{2} (x)

Manipulating left side

sec (x) cos (- x) - sin^{2} (x)

Use the negative angle identity:

cos (- x) = cos (x)

= - sin^{2} (x) + cos (x) sec (x)

Express with sin, cos

- sin^{2} (x) + cos (x) sec (x)

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= - sin^{2} (x) + cos (x) \frac{1}{cos ( x )}

Simplify

- sin^{2} (x) + cos (x) \frac{1}{cos ( x )} : - sin^{2} (x) + 1

- sin^{2} (x) + cos (x) \frac{1}{cos ( x )}

cos (x) \frac{1}{cos ( x )} = 1

cos (x) \frac{1}{cos ( x )}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot cos ( x )}{cos ( x )}

Cancel the common factor:

cos (x)

= 1

= - sin^{2} (x) + 1

= - sin^{2} (x) + 1

= 1 - sin^{2} (x)

Rewrite using trig identities

1 - sin^{2} (x)

Use the Pythagorean identity:

1 = cos^{2} (x) + sin^{2} (x)

1 - sin^{2} (x) = cos^{2} (x)

= cos^{2} (x)

= cos^{2} (x)

We showed that the two sides could take the same form

\Rightarrow True

sec^{2} (x) cos (x) - sec (x) = 0

sin^{4} (x) = (1 - cos^{2} (x))^{2}

sec (z) cot (z) sin (z) = 1

cos (θ) = \frac{2}{3}

cos (4 x) + sin (4 x) = cos (2 x)

Is sec(x)cos(-x)-sin^2(x)=cos^2(x) ?
The answer to whether sec(x)cos(-x)-sin^2(x)=cos^2(x) is True