Is sin^2(α)sec(α)=tan^2(α) ?

The answer to whether sin^2(α)sec(α)=tan^2(α) is False

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prove sin^2(α)sec(α)=tan^2(α)

prove

sin^{2} (α) sec (α) = tan^{2} (α)

False

Solution steps

sin^{2} (α) sec (α) = tan^{2} (α)

Show that the two sides are not equal

For

sin^{2} (α) sec (α) = tan^{2} (α)

plug in

α = 1

sin^{2} (1) sec (1) = 1.31051 \dots

sin^{2} (1) sec (1)

Refine to a decimal form

= 1.31051 \dots

tan^{2} (1) = 2.42551 \dots

tan^{2} (1)

Refine to a decimal form

= 2.42551 \dots

The two sides are not equal

\Rightarrow False

1 + tan (2 x) tan (x) = sec (2 x)

\frac{4}{cos ^{2} ( x )} - 5 = 4 tan^{2} (x) - 1

(sec (x) + tan (x)) (1 - sec (x)) = cos (x)

tan (x) cos (2 x) = sin (2 x) - tan (x)

\frac{sin ^{2} ( θ )}{tan ^{2} ( θ )} = cos^{2} (θ)

Is sin^2(α)sec(α)=tan^2(α) ?
The answer to whether sin^2(α)sec(α)=tan^2(α) is False