Is cos^2(x)-sin^2(x)=1-sin^2(x) ?

The answer to whether cos^2(x)-sin^2(x)=1-sin^2(x) is False

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prove cos^2(x)-sin^2(x)=1-sin^2(x)

prove

cos^{2} (x) - sin^{2} (x) = 1 - sin^{2} (x)

False

Solution steps

cos^{2} (x) - sin^{2} (x) = 1 - sin^{2} (x)

Show that the two sides are not equal

For

cos^{2} (x) - sin^{2} (x) = 1 - sin^{2} (x)

plug in

x = 1

cos^{2} (1) - sin^{2} (1) = - 0.41614 \dots

cos^{2} (1) - sin^{2} (1)

Refine to a decimal form

= - 0.41614 \dots

1 - sin^{2} (1) = 0.29192 \dots

1 - sin^{2} (1)

Refine to a decimal form

= 0.29192 \dots

The two sides are not equal

\Rightarrow False

sin (x) \cdot tan (x) + cos (x) = sec (x)

cot (α - β) = \frac{cot ( α ) cot ( β ) + 1}{cot ( β ) - cot ( α )}

tan (2 x) = tan (x + x)

sin^{3} (x) = \frac{3}{4} sin (x) - \frac{1}{4} sin (3 x)

cos^{2} (x) = (1 - sin (x)) (1 + sin (x))

Is cos^2(x)-sin^2(x)=1-sin^2(x) ?
The answer to whether cos^2(x)-sin^2(x)=1-sin^2(x) is False