Is sec(A)csc(A)=sec(A)cot(A) ?

The answer to whether sec(A)csc(A)=sec(A)cot(A) is False

Popular >

prove sec(A)csc(A)=sec(A)cot(A)

prove

sec (A) csc (A) = sec (A) cot (A)

False

Solution steps

sec (A) csc (A) = sec (A) cot (A)

Show that the two sides are not equal

For

sec (A) csc (A) = sec (A) cot (A)

plug in

A = 1

sec (1) csc (1) = 2.19950 \dots

sec (1) csc (1)

Refine to a decimal form

= 2.19950 \dots

sec (1) cot (1) = 1.18839 \dots

sec (1) cot (1)

Refine to a decimal form

= 1.18839 \dots

The two sides are not equal

\Rightarrow False

1 - 2 sin^{2} (x) = - 1 + 2 cos^{2} (x)

\frac{1}{cos ( x )} - sin (x) tan (x) = cos (x)

\frac{cos ( 5 x ) + cos ( 3 x )}{sin ( 5 x ) + sin ( 3 x )} = cot (4 x)

cos^{2} (\frac{x}{2}) = \frac{1 + cos ( x )}{2}

\frac{sin ( x ) + cos ( x )}{sin ( x )} = 1 + cot (x)

Is sec(A)csc(A)=sec(A)cot(A) ?
The answer to whether sec(A)csc(A)=sec(A)cot(A) is False