Is 9(1+sin(y))(1+sin(-y))=9cos^2(y) ?

The answer to whether 9(1+sin(y))(1+sin(-y))=9cos^2(y) is True

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

prove 9(1+sin(y))(1+sin(-y))=9cos^2(y)

prove

9 (1 + sin (y)) (1 + sin (- y)) = 9 cos^{2} (y)

True

Solution steps

9 (1 + sin (y)) (1 + sin (- y)) = 9 cos^{2} (y)

Manipulating left side

9 (1 + sin (y)) (1 + sin (- y))

Use the negative angle identity:

sin (- x) = - sin (x)

= 9 (1 - sin (y)) (1 + sin (y))

Rewrite using trig identities

9 (1 - sin (y)) (1 + sin (y))

Expand

(1 + sin (y)) (1 - sin (y)) : 1 - sin^{2} (y)

(1 + sin (y)) (1 - sin (y))

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = 1, b = sin (y)

= 1^{2} - sin^{2} (y)

Apply rule

1^{a} = 1

1^{2} = 1

= 1 - sin^{2} (y)

= 9 (1 - sin^{2} (y))

Use the Pythagorean identity:

1 = cos^{2} (y) + sin^{2} (y)

1 - sin^{2} (y) = cos^{2} (y)

= 9 cos^{2} (y)

= 9 cos^{2} (y)

We showed that the two sides could take the same form

\Rightarrow True

(\frac{tan ( θ )}{sec ( θ )}) = sin (θ)

sin (4 5^{\circ}) cot (4 5^{\circ}) = cos (4 5^{\circ})

sec (4 x) = 2

\frac{1}{cos ^{2} ( A )} + \frac{1}{cot ^{2} ( A )} = 1

csc (θ) - sin (θ) = cot (θ) csc (θ)

Is 9(1+sin(y))(1+sin(-y))=9cos^2(y) ?
The answer to whether 9(1+sin(y))(1+sin(-y))=9cos^2(y) is True