Is ((tan(x)cot(x)))/(cos(x))=sec(x) ?

The answer to whether ((tan(x)cot(x)))/(cos(x))=sec(x) is True

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prove ((tan(x)cot(x)))/(cos(x))=sec(x)

prove

\frac{( tan ( x ) cot ( x ) )}{cos ( x )} = sec (x)

True

Solution steps

\frac{tan ( x ) cot ( x )}{cos ( x )} = sec (x)

Manipulating left side

\frac{tan ( x ) cot ( x )}{cos ( x )}

Express with sin, cos

\frac{cot ( x ) tan ( x )}{cos ( x )}

Use the basic trigonometric identity:

cot (x) = \frac{cos ( x )}{sin ( x )}

= \frac{\frac{c o s ( x )}{s i n ( x )} tan ( x )}{cos ( x )}

Use the basic trigonometric identity:

tan (x) = \frac{sin ( x )}{cos ( x )}

= \frac{\frac{c o s ( x )}{s i n ( x )} \cdot \frac{s i n ( x )}{c o s ( x )}}{cos ( x )}

Simplify

\frac{\frac{c o s ( x )}{s i n ( x )} \cdot \frac{s i n ( x )}{c o s ( x )}}{cos ( x )} : \frac{1}{cos ( x )}

\frac{\frac{c o s ( x )}{s i n ( x )} \cdot \frac{s i n ( x )}{c o s ( x )}}{cos ( x )}

Multiply

\frac{cos ( x )}{sin ( x )} \cdot \frac{sin ( x )}{cos ( x )} : 1

\frac{cos ( x )}{sin ( x )} \cdot \frac{sin ( x )}{cos ( x )}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{cos ( x ) sin ( x )}{sin ( x ) cos ( x )}

Cancel the common factor:

cos (x)

= \frac{sin ( x )}{sin ( x )}

Cancel the common factor:

sin (x)

= 1

= \frac{1}{cos ( x )}

= \frac{1}{cos ( x )}

= \frac{1}{cos ( x )}

Rewrite using trig identities

Use the basic trigonometric identity:

cos (x) = \frac{1}{sec ( x )}

\frac{1}{\frac{1}{s e c ( x )}}

Simplify

\frac{1}{\frac{1}{s e c ( x )}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{sec ( x )}{1}

Apply rule

\frac{a}{1} = a

= sec (x)

sec (x)

sec (x)

We showed that the two sides could take the same form

\Rightarrow True

2 cos (2 x) = sin (2 x + 90)

\frac{sec ( a ) + csc ( a )}{1 + tan ( a )} = csc (a)

cot (\frac{t}{2}) = \frac{sin ( t )}{1 - cos ( t )}

1 - \frac{cos ^{2} ( x )}{1 + sin ^{2} ( x )} = sin (x)

\frac{1}{2} sec (x) - 1 = 0

Is ((tan(x)cot(x)))/(cos(x))=sec(x) ?
The answer to whether ((tan(x)cot(x)))/(cos(x))=sec(x) is True