Is 4(5cos(2x))+(-20cos(2x))=0 ?

The answer to whether 4(5cos(2x))+(-20cos(2x))=0 is True

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prove 4(5cos(2x))+(-20cos(2x))=0

prove

4 (5 cos (2 x)) + (- 20 cos (2 x)) = 0

True

Solution steps

4 \cdot 5 cos (2 x) - 20 cos (2 x) = 0

Manipulating left side

45 cos (2 x) - 20 cos (2 x)

Simplify

= 0

We showed that the two sides could take the same form

\Rightarrow True

\frac{( 1 + cos ( 2 x ) )}{1 - cos ( 2 x )} = cot^{2} (x)

2 cos (2 x) - 1 = 1 - 2 sin (2 x)

(3 sin (x) - 3 cos (x))^{2} = - 9 sin (2 x) + 9

- 5 cos (0) - 8.6602500000000 \dots sin (0) = - 5

0 sin (\frac{π}{2}) + 1 = cos (2 π)

Is 4(5cos(2x))+(-20cos(2x))=0 ?
The answer to whether 4(5cos(2x))+(-20cos(2x))=0 is True