Is sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) ?

The answer to whether sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) is False

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prove sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ))

prove

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

False

Solution steps

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

Show that the two sides are not equal

For

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

plug in

θ = 1

sin (1) - tan (1) = - 0.71593 \dots

sin (1) - tan (1)

Refine to a decimal form

= - 0.71593 \dots

\frac{sin ( 1 )}{1 - cos ( 1 )} = 1.83048 \dots

\frac{sin ( 1 )}{1 - cos ( 1 )}

Refine to a decimal form

= 1.83048 \dots

The two sides are not equal

\Rightarrow False

sin^{2} (u) = \frac{( 1 - cos ( 2 u ) )}{2}

tan (θ) - sec (θ) = - \frac{cos ( θ )}{1 + sin ( θ )}

2 cos^{2} (x) - 1 = - 2 sin^{2} (x) + 1

sin (x) = - 1 = sin (0) = - 1

sin (\frac{3 π}{2} - θ) = cos (θ)

Is sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) ?
The answer to whether sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) is False