Is 5(sin^2(x)-1)=5cot^2(x) ?

The answer to whether 5(sin^2(x)-1)=5cot^2(x) is False

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prove 5(sin^2(x)-1)=5cot^2(x)

prove

5 (sin^{2} (x) - 1) = 5 cot^{2} (x)

False

Solution steps

5 (sin^{2} (x) - 1) = 5 cot^{2} (x)

Show that the two sides are not equal

For

5 (sin^{2} (x) - 1) = 5 cot^{2} (x)

plug in

x = 1

5 (sin^{2} (1) - 1) = - 1.45963 \dots

5 (sin^{2} (1) - 1)

Refine to a decimal form

= - 1.45963 \dots

5 cot^{2} (1) = 2.06141 \dots

5 cot^{2} (1)

Refine to a decimal form

= 2.06141 \dots

The two sides are not equal

\Rightarrow False

\frac{sec ^{2} ( x )}{tan ( x )} = cot (x) + tan (x)

cos (z) = sin (\frac{π}{2} + z)

sin^{2} (θ) (2 + cot^{2} (θ)) = 1

5 sin (x) \cdot cos (x) = 5 (1 - cos^{2} (x)) cot (x)

- cos^{2} (2 θ) = \frac{1 + cos ( 4 θ )}{8}

Is 5(sin^2(x)-1)=5cot^2(x) ?
The answer to whether 5(sin^2(x)-1)=5cot^2(x) is False