Is (sin(60))/(1-cos(60))=cot(30) ?

The answer to whether (sin(60))/(1-cos(60))=cot(30) is True

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prove (sin(60))/(1-cos(60))=cot(30)

Solution

prove

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} = cot (3 0^{\circ})

Solution

True

Solution steps

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} = cot (3 0^{\circ})

Manipulating left side

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )}

Simplify

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )} : 3

\frac{sin ( 6 0 ^{\circ} )}{1 - cos ( 6 0 ^{\circ} )}

sin (6 0^{\circ}) = \frac{3}{2}

sin (6 0^{\circ})

Use the following trivial identity:

sin (6 0^{\circ}) = \frac{3}{2}

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{\frac{3}{2}}{1 - cos ( 6 0 ^{\circ} )}

1 - cos (6 0^{\circ}) = 1 - \frac{1}{2}

1 - cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1 - \frac{1}{2}

= \frac{\frac{3}{2}}{1 - \frac{1}{2}}

Simplify

\frac{\frac{3}{2}}{1 - \frac{1}{2}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 ( 1 - \frac{1}{2} )}

Join

1 - \frac{1}{2} : \frac{1}{2}

1 - \frac{1}{2}

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 - 1}{2}

1 \cdot 2 - 1 = 1

1 \cdot 2 - 1

Multiply the numbers:

1 \cdot 2 = 2

= 2 - 1

Subtract the numbers:

2 - 1 = 1

= 1

= \frac{1}{2}

= \frac{3}{2 \cdot \frac{1}{2}}

Multiply

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2}{2}

Cancel the common factor:

2

= 1

= \frac{3}{1}

Apply rule

\frac{a}{1} = a

= 3

= 3

= 3

Manipulating right side

cot (3 0^{\circ})

Simplify

= 3

We showed that the two sides could take the same form

\Rightarrow True

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Is (sin(60))/(1-cos(60))=cot(30) ?
The answer to whether (sin(60))/(1-cos(60))=cot(30) is True