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人気のある >

sin^2(2x)+3sin(2x)+2=0,0<= x<= 10pi

解

sin^{2} (2 x) + 3 sin (2 x) + 2 = 0, 0 \leq x \leq 10 π

解

x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = \frac{11 π}{4}, x = \frac{15 π}{4}, x = \frac{19 π}{4}

+1

度

x = 13 5^{\circ}, x = 31 5^{\circ}, x = 49 5^{\circ}, x = 67 5^{\circ}, x = 85 5^{\circ}

解答ステップ

sin^{2} (2 x) + 3 sin (2 x) + 2 = 0, 0 \leq x \leq 10 π

置換で解く

sin^{2} (2 x) + 3 sin (2 x) + 2 = 0

仮定:

sin (2 x) = u

u^{2} + 3 u + 2 = 0

u^{2} + 3 u + 2 = 0 : u = - 1, u = - 2

u^{2} + 3 u + 2 = 0

解くとthe二次式

u^{2} + 3 u + 2 = 0

二次Equationの公式:

次の場合:

a = 1, b = 3, c = 2

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

3^{2} - 4 \cdot 1 \cdot 2

数を乗じる:

4 \cdot 1 \cdot 2 = 8

= 3^{2} - 8

3^{2} = 9

= 9 - 8

数を引く:

9 - 8 = 1

= 1

規則を適用

1 = 1

= 1

u_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

解を分離する

u_{1} = \frac{- 3 + 1}{2 \cdot 1}, u_{2} = \frac{- 3 - 1}{2 \cdot 1}

u = \frac{- 3 + 1}{2 \cdot 1} : - 1

\frac{- 3 + 1}{2 \cdot 1}

数を足す/引く:

- 3 + 1 = - 2

= \frac{- 2}{2 \cdot 1}

数を乗じる:

2 \cdot 1 = 2

= \frac{- 2}{2}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2}

規則を適用

\frac{a}{a} = 1

= - 1

u = \frac{- 3 - 1}{2 \cdot 1} : - 2

\frac{- 3 - 1}{2 \cdot 1}

数を引く:

- 3 - 1 = - 4

= \frac{- 4}{2 \cdot 1}

数を乗じる:

2 \cdot 1 = 2

= \frac{- 4}{2}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{2}

数を割る:

\frac{4}{2} = 2

= - 2

二次equationの解:

u = - 1, u = - 2

代用を戻す

u = sin (2 x)

sin (2 x) = - 1, sin (2 x) = - 2

sin (2 x) = - 1, sin (2 x) = - 2

sin (2 x) = - 1, 0 \leq x \leq 10 π : x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = \frac{11 π}{4}, x = \frac{15 π}{4}, x = \frac{19 π}{4}

sin (2 x) = - 1, 0 \leq x \leq 10 π

以下の一般解

sin (2 x) = - 1

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

2 x = \frac{3 π}{2} + 2 πn

2 x = \frac{3 π}{2} + 2 πn

解く

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

2 x = \frac{3 π}{2} + 2 πn

以下で両辺を割る

2

2 x = \frac{3 π}{2} + 2 πn

以下で両辺を割る

2

\frac{2 x}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 x}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 x}{2} : x

\frac{2 x}{2}

数を割る:

\frac{2}{2} = 1

= x

簡素化

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2} : \frac{3 π}{4} + πn

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{3 π}{2}}{2} = \frac{3 π}{4}

\frac{\frac{3 π}{2}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{3 π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

数を割る:

\frac{2}{2} = 1

= πn

= \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

範囲の解答

0 \leq x \leq 10 π

x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = \frac{11 π}{4}, x = \frac{15 π}{4}, x = \frac{19 π}{4}

sin (2 x) = - 2, 0 \leq x \leq 10 π :

解なし

sin (2 x) = - 2, 0 \leq x \leq 10 π

- 1 \leq sin (x) \leq 1

解なし

すべての解を組み合わせる

x = \frac{3 π}{4}, x = \frac{7 π}{4}, x = \frac{11 π}{4}, x = \frac{15 π}{4}, x = \frac{19 π}{4}

グラフ

人気の例

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cos (x) + 3 sin (x) = 2

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