Is sin^4(u)-cos^4(u)=2sin^2(u)-1 ?

The answer to whether sin^4(u)-cos^4(u)=2sin^2(u)-1 is True

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prove sin^4(u)-cos^4(u)=2sin^2(u)-1

prove

sin^{4} (u) - cos^{4} (u) = 2 sin^{2} (u) - 1

True

Solution steps

sin^{4} (u) - cos^{4} (u) = 2 sin^{2} (u) - 1

Manipulating left side

sin^{4} (u) - cos^{4} (u)

Factor

- cos^{4} (u) + sin^{4} (u) : (sin^{2} (u) + cos^{2} (u)) (sin (u) + cos (u)) (sin (u) - cos (u))

- cos^{4} (u) + sin^{4} (u)

Rewrite

sin^{4} (u) - cos^{4} (u)

(sin^{2} (u))^{2} - (cos^{2} (u))^{2}

sin^{4} (u) - cos^{4} (u)

Apply exponent rule:

a^{b c} = (a^{b})^{c}

sin^{4} (u) = (sin^{2} (u))^{2}

= (sin^{2} (u))^{2} - cos^{4} (u)

Apply exponent rule:

a^{b c} = (a^{b})^{c}

cos^{4} (u) = (cos^{2} (u))^{2}

= (sin^{2} (u))^{2} - (cos^{2} (u))^{2}

= (sin^{2} (u))^{2} - (cos^{2} (u))^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(sin^{2} (u))^{2} - (cos^{2} (u))^{2} = (sin^{2} (u) + cos^{2} (u)) (sin^{2} (u) - cos^{2} (u))

= (sin^{2} (u) + cos^{2} (u)) (sin^{2} (u) - cos^{2} (u))

Factor

sin^{2} (u) - cos^{2} (u) : (sin (u) + cos (u)) (sin (u) - cos (u))

sin^{2} (u) - cos^{2} (u)

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

sin^{2} (u) - cos^{2} (u) = (sin (u) + cos (u)) (sin (u) - cos (u))

= (sin (u) + cos (u)) (sin (u) - cos (u))

= (sin^{2} (u) + cos^{2} (u)) (sin (u) + cos (u)) (sin (u) - cos (u))

= (- cos (u) + sin (u)) (cos (u) + sin (u)) (cos^{2} (u) + sin^{2} (u))

Rewrite using trig identities

(- cos (u) + sin (u)) (cos (u) + sin (u)) (cos^{2} (u) + sin^{2} (u))

Expand

(sin (u) + cos (u)) (sin (u) - cos (u)) : sin^{2} (u) - cos^{2} (u)

(sin (u) + cos (u)) (sin (u) - cos (u))

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = sin (u), b = cos (u)

= sin^{2} (u) - cos^{2} (u)

= (sin^{2} (u) - cos^{2} (u)) (cos^{2} (u) + sin^{2} (u))

Use the Double Angle identity:

cos^{2} (u) - sin^{2} (u) = cos (2 u)

- cos^{2} (u) + sin^{2} (u) = - cos (2 u)

= (- cos (2 u)) (cos^{2} (u) + sin^{2} (u))

Simplify

= - cos (2 u) (cos^{2} (u) + sin^{2} (u))

Use the Double Angle identity:

cos (2 x) = 1 - 2 sin^{2} (x)

= - (1 - 2 sin^{2} (u)) (cos^{2} (u) + sin^{2} (u))

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= - (1 - 2 sin^{2} (u)) \cdot 1

Simplify

- (1 - 2 sin^{2} (u)) \cdot 1 : - 1 + 2 sin^{2} (u)

- (1 - 2 sin^{2} (u)) \cdot 1

Multiply:

(1 - 2 sin^{2} (u)) \cdot 1 = (1 - 2 sin^{2} (u))

= - (- 2 sin^{2} (u) + 1)

Distribute parentheses

= - (1) - (- 2 sin^{2} (u))

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - 1 + 2 sin^{2} (u)

= - 1 + 2 sin^{2} (u)

= - 1 + 2 sin^{2} (u)

= 2 sin^{2} (u) - 1

We showed that the two sides could take the same form

\Rightarrow True

tan^{4} (x) - sec^{4} (x) = - 2 sec^{2} (x) + 1

(tan (x) + cot (x)) tan (x) = sec^{2} (x)

(cos (x) + sin (x))^{2} - 2 sin (x) cos (x) = 1

1 - cos^{2} (x) = \frac{tan ^{2} ( x )}{sec ^{2} ( x )}

(1 - sin^{2} (a)) sec^{2} (a) - 1 = 0

Is sin^4(u)-cos^4(u)=2sin^2(u)-1 ?
The answer to whether sin^4(u)-cos^4(u)=2sin^2(u)-1 is True