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人気のある Word Problems >

the sum of three consecutive odd numbers is greater than 111. Find the smallest possible product of these three numbers

解

t h e s u m o f t h ree co n sec u t i v e o dd n u mb ers i s g re a t er t han 111. F in d t h e s ma ll es t p oss ib l e p ro d u c t o f t h ese t h ree n u mb ers

解

x > 35

解答ステップ

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

x + x + 2 + x + 4 > 111

解く

x + x + 2 + x + 4 > 111 : x > 35

x > 35

人気の例

the forth number of(x+2/x)^6 30% of a number is 90 sqrt(1476) as a number the sum of twice a number x and 7 is at most 3 5 is an integer