sqrt(2\sqrt{2x+3)}=sqrt(x+3)

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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√2√2x+3=√x+3

Solution

x=3, x=−1

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Solution steps

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√2√2x+3=√x+3

Remove square roots

8x+12=x²+6x+9

Solve 8x+12=x²+6x+9: x=3, x=−1

x=3, x=−1

Verify Solutions: x=3 True, x=−1 True

The solutions are

x=3, x=−1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sqrt(2\sqrt{2x+3)}=sqrt(x+3)

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