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sqrt(2\sqrt{7x+8)}=sqrt(2x+4)

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x2 x□ log□ √☐ □√☐ ≤ ≥ □□  · ÷ x◦ π
(☐)′ ddx  ∂∂x  ∫ ∫□□ lim ∑ ∞ θ (f ◦ g) f(x)
−▭▭ < 7 8 9 ÷ AC
+▭▭ > 4 5 6 × ☐☐☐ 
×▭▭ ( 1 2 3 − x
▭ |▭ ) . 0 = + y
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√2√7x+8=√2x+4
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\sqrt{2\sqrt{7x+8}}=\sqrt{2x+4}

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