implicit derivative of (dy)/(dx),(x+2)^2+(y-3)^2=37

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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implicit derivative dydx , (x+2)²+(y−3)²=37

Solution

dydx =−x+2y−3

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(x+2)²+(y−3)²=37

Treat y as y(x)

Differentiate both sides: 2x+2ydydx −6dydx +4=0

Isolate dydx : dydx =−x+2y−3

dydx =−x+2y−3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

implicit derivative of (dy)/(dx),(x+2)^2+(y-3)^2=37

Solution

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