Example
A group of mathematicians are getting together for a conference. The members are coming from four cities: Seattle, Tacoma, Puyallup, and Olympia. Their approximate locations on a map are shown below.

The votes for where to hold the conference were:
|
51 |
25 |
10 |
14 |
1st choice |
Seattle |
Tacoma |
Puyallup |
Olympia |
2nd choice |
Tacoma |
Puyallup |
Tacoma |
Tacoma |
3rd choice |
Olympia |
Olympia |
Olympia |
Puyallup |
4th choice |
Puyallup |
Seattle |
Seattle |
Seattle |
Use the Borda count method to determine the winning town for the conference.
Answer:
In each of the 51 ballots ranking Seattle first, Puyallup will be given 1 point, Olympia 2 points, Tacoma 3 points, and Seattle 4 points. Multiplying the points per vote times the number of votes allows us to calculate points awarded
|
51 |
25 |
10 |
14 |
1st choice 4 points |
Seattle
4⋅51=204 |
Tacoma
4⋅25=100 |
Puyallup
4cot10=40 |
Olympia
4⋅14=56 |
2nd choice 3 points |
Tacoma
3⋅51=153 |
Puyallup
3⋅25=75 |
Tacoma
3⋅10=30 |
Tacoma
3⋅14=42 |
3rd choice 2 points |
Olympia
2⋅51=102 |
Olympia
2⋅25=50 |
Olympia
2⋅10=20 |
Puyallup
2⋅14=28 |
4th choice 1 point |
Puyallup
1⋅51=51 |
Seattle
1⋅25=25 |
Seattle
1⋅10=10 |
Seattle
1⋅14=14 |
Adding up the points:
Seattle:
204+25+10+14=253 points
Tacoma:
153+100+30+42=325 points
Puyallup:
51+75+40+28=194 points
Olympia:
102+50+20+56=228 points
Under the Borda Count method, Tacoma is the winner of this vote.
Here is a video showing the example from above.
https://youtu.be/vfujywLdW_s?list=PL1F887D3B8BF7C297
Try It
Consider again the election from earlier. Find the winner using Borda Count. Since we have some incomplete preference ballots, for simplicity, give every unranked candidate 1 point, the points they would normally get for last place.
|
44 |
14 |
20 |
70 |
22 |
80 |
39 |
1st choice |
G |
G |
G |
M |
M |
B |
B |
2nd choice |
M |
B |
|
G |
B |
M |
|
3rd choice |
B |
M |
|
B |
G |
G |
|