erweitern (B+BC)(B+B^'C)(B+D)

Lösung

erweitern

(B + BC) (B + B^{^{'}} C) (B + D)

B^{3} + D B^{2} + C B^{' + 2} + D C B^{1 +'} + B^{3} C + D B^{2} C + C^{2} B^{' + 2} + D C^{2} B^{1 +'}

Schritte zur Lösung

(B + BC) (B + B^{^{'}} C) (B + D)

= (B + BC) (B + C B^{^{^{'}}}) (B + D)

Multipliziere aus

(B + BC) (B + B^{^{'}} C) : B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}

= (B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}) (B + D)

Multipliziere aus

(B^{2} + C B^{1 +^{'}} + B^{2} C + C^{2} B^{1 +^{'}}) (B + D) : B^{3} + D B^{2} + C B^{^{'} + 2} + D C B^{1 +^{'}} + B^{3} C + D B^{2} C + C^{2} B^{^{'} + 2} + D C^{2} B^{1 +^{'}}

= B^{3} + D B^{2} + C B^{^{'} + 2} + D C B^{1 +^{'}} + B^{3} C + D B^{2} C + C^{2} B^{^{'} + 2} + D C^{2} B^{1 +^{'}}

e x p an d - 3 (2 x + 5 y = 17)

e x p an d - \frac{7}{( x + 4 ) ^{2}}

\frac{\partial}{\partial x} ((z) (x y^{3} - x^{2} y))

e x p an d (5 n^{6} + 2 n^{4}) n

e x p an d - \frac{( s + 1 ) ( s - 2 )}{a - s ^{2} + s + 2}