What are the solutions to the equation x^2+12x+36=7 ?

The solutions to the equation x^2+12x+36=7 are x=-6+sqrt(7),x=-6-sqrt(7)

Find the zeros of x^2+12x+36=7

The zeros of x^2+12x+36=7 are x=-6+sqrt(7),x=-6-sqrt(7)

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x^{2} + 12 x + 36 = 7

x = - 6 + 7, x = - 6 - 7

Decimal Notation

x = - 3.35424 \dots, x = - 8.64575 \dots

Solution steps

x^{2} + 12 x + 36 = 7

Move

7

to the left side

x^{2} + 12 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 29}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 29 = 27

x_{1, 2} = \frac{- 12 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 7}{2 \cdot 1}

x = \frac{- 12 + 2 7}{2 \cdot 1} : - 6 + 7

x = \frac{- 12 - 2 7}{2 \cdot 1} : - 6 - 7

The solutions to the quadratic equation are:

x = - 6 + 7, x = - 6 - 7

(- \frac{1}{4})^{2}

x^{2} - 6 x - 9 = 0

x^{2} + 4 x y + 3 y^{2}

- x^{2} + 3 x = x^{2} + x - 4

\frac{1}{\frac{- 1}{4}}

What are the solutions to the equation x^2+12x+36=7 ?
The solutions to the equation x^2+12x+36=7 are x=-6+sqrt(7),x=-6-sqrt(7)
Find the zeros of x^2+12x+36=7
The zeros of x^2+12x+36=7 are x=-6+sqrt(7),x=-6-sqrt(7)