What are the solutions to the equation x^2-6x-9=0 ?

The solutions to the equation x^2-6x-9=0 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

Find the zeros of x^2-6x-9=0

The zeros of x^2-6x-9=0 are x=3(1+sqrt(2)),x=3(1-sqrt(2))

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x^{2} - 6 x - 9 = 0

x = 3 (1 + 2), x = 3 (1 - 2)

Decimal Notation

x = 7.24264 \dots, x = - 1.24264 \dots

Solution steps

x^{2} - 6 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 9) = 62

x_{1, 2} = \frac{- ( - 6 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 2}{2 \cdot 1} : 3 (1 + 2)

x = \frac{- ( - 6 ) - 6 2}{2 \cdot 1} : 3 (1 - 2)

The solutions to the quadratic equation are:

x = 3 (1 + 2), x = 3 (1 - 2)

x^{2} + 4 x y + 3 y^{2}

- x^{2} + 3 x = x^{2} + x - 4

\frac{1}{\frac{- 1}{4}}

4 x^{2} - 30 x + 45 = 0

0 = 2 x^{2} - 2 x - 760

What are the solutions to the equation x^2-6x-9=0 ?
The solutions to the equation x^2-6x-9=0 are x=3(1+sqrt(2)),x=3(1-sqrt(2))
Find the zeros of x^2-6x-9=0
The zeros of x^2-6x-9=0 are x=3(1+sqrt(2)),x=3(1-sqrt(2))