t^2-10t+16=0

解

t^{2} - 10 t + 16 = 0

t = 8, t = 2

解答ステップ

t^{2} - 10 t + 16 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 16 = 6

t_{1, 2} = \frac{- ( - 10 ) \pm 6}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 10 ) + 6}{2 \cdot 1}, t_{2} = \frac{- ( - 10 ) - 6}{2 \cdot 1}

t = \frac{- ( - 10 ) + 6}{2 \cdot 1} : 8

t = \frac{- ( - 10 ) - 6}{2 \cdot 1} : 2

二次equationの解:

t = 8, t = 2