12x^2-488x+3321=0

解答

12 x^{2} - 488 x + 3321 = 0

x = \frac{122 + 4921}{6}, x = \frac{122 - 4921}{6}

十进制

x = 32.02497 \dots, x = 8.64169 \dots

求解步骤

12 x^{2} - 488 x + 3321 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 488 ) \pm ( - 488 ) ^{2} - 4 \cdot 12 \cdot 3321}{2 \cdot 12}

(- 488)^{2} - 4 \cdot 12 \cdot 3321 = 44921

x_{1, 2} = \frac{- ( - 488 ) \pm 4 4921}{2 \cdot 12}

将解分隔开

x_{1} = \frac{- ( - 488 ) + 4 4921}{2 \cdot 12}, x_{2} = \frac{- ( - 488 ) - 4 4921}{2 \cdot 12}

x = \frac{- ( - 488 ) + 4 4921}{2 \cdot 12} : \frac{122 + 4921}{6}

x = \frac{- ( - 488 ) - 4 4921}{2 \cdot 12} : \frac{122 - 4921}{6}

二次方程组的解是:

x = \frac{122 + 4921}{6}, x = \frac{122 - 4921}{6}

so l v e f or x, 4 z^{2} - x^{2} - y + 16 z + 4 z + 20 = 0

\frac{3 ( - x + 2 )}{5} + 4 x (\frac{- 2 x + 1}{3}) = x (- 3 x + 1) - \frac{1}{2}

(x + 4) 2 x = (x + 1) (x - 1) - 23

co m pl e t es q u a re - x^{2} - 2 x + 5

(2 x + 1)^{2} - 10 x = 19