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受欢迎的代数 >

(3(-x+2))/5+4x((-2x+1)/3)=x(-3x+1)-1/2

解答

\frac{3 ( - x + 2 )}{5} + 4 x (\frac{- 2 x + 1}{3}) = x (- 3 x + 1) - \frac{1}{2}

解答

x = \frac{2}{5} + i \frac{494}{10}, x = \frac{2}{5} - i \frac{494}{10}

求解步骤

\frac{3 ( - x + 2 )}{5} + 4 x (\frac{- 2 x + 1}{3}) = x (- 3 x + 1) - \frac{1}{2}

找到

5, 2

的最小公倍数:

10

乘以最小公倍数=

10

\frac{3 ( - x + 2 )}{5} \cdot 10 + 4 x \frac{- 2 x + 1}{3} \cdot 10 = x (- 3 x + 1) \cdot 10 - \frac{1}{2} \cdot 10

化简

6 (- x + 2) + \frac{40 x ( - 2 x + 1 )}{3} = 10 x (- 3 x + 1) - 5

展开

6 (- x + 2) + \frac{40 x ( - 2 x + 1 )}{3} : - \frac{80 x ^{2}}{3} + \frac{22 x}{3} + 12

展开

10 x (- 3 x + 1) - 5 : - 30 x^{2} + 10 x - 5

- \frac{80 x ^{2}}{3} + \frac{22 x}{3} + 12 = - 30 x^{2} + 10 x - 5

将

5

para o lado esquerdo

\frac{- 80 x ^{2} + 22 x}{3} + 17 = - 30 x^{2} + 10 x

将

10 x

para o lado esquerdo

\frac{- 80 x ^{2} - 8 x}{3} + 17 = - 30 x^{2}

将

30 x^{2}

para o lado esquerdo

\frac{10 x ^{2} - 8 x}{3} + 17 = 0

改写成标准形式

a x^{2} + b x + c = 0

\frac{10 x ^{2}}{3} - \frac{8 x}{3} + 17 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - \frac{8}{3} ) \pm ( - \frac{8}{3} ) ^{2} - 4 \cdot \frac{10}{3} \cdot 17}{2 \cdot \frac{10}{3}}

化简

(- \frac{8}{3})^{2} - 4 \cdot \frac{10}{3} \cdot 17 : i \frac{2 494}{3}

x_{1, 2} = \frac{- ( - \frac{8}{3} ) \pm i \frac{2 494}{3}}{2 \cdot \frac{10}{3}}

将解分隔开

x_{1} = \frac{- ( - \frac{8}{3} ) + i \frac{2 494}{3}}{2 \cdot \frac{10}{3}}, x_{2} = \frac{- ( - \frac{8}{3} ) - i \frac{2 494}{3}}{2 \cdot \frac{10}{3}}

x = \frac{- ( - \frac{8}{3} ) + i \frac{2 494}{3}}{2 \frac{10}{3}} : \frac{2}{5} + i \frac{494}{10}

x = \frac{- ( - \frac{8}{3} ) - i \frac{2 494}{3}}{2 \frac{10}{3}} : \frac{2}{5} - i \frac{494}{10}

二次方程组的解是:

x = \frac{2}{5} + i \frac{494}{10}, x = \frac{2}{5} - i \frac{494}{10}

作图

流行的例子

(x+4)2x=(x+1)(x-1)-23

(x + 4) 2 x = (x + 1) (x - 1) - 23

completesquare-x^2-2x+5

co m pl e t es q u a re - x^{2} - 2 x + 5

(2x+1)^2-10x=19

(2 x + 1)^{2} - 10 x = 19

2x^2+2x^2+x+x-2=0

2 x^{2} + 2 x^{2} + x + x - 2 = 0

solvefor a,a^2-2ab+b^2=1

so l v e f or a, a^{2} - 2 ab + b^{2} = 1