-2x^2+12x-5=0

Lösung

- 2 x^{2} + 12 x - 5 = 0

x = \frac{6 - 26}{2}, x = \frac{6 + 26}{2}

Dezimale

x = 0.45049 \dots, x = 5.54950 \dots

Schritte zur Lösung

- 2 x^{2} + 12 x - 5 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 5) = 226

x_{1, 2} = \frac{- 12 \pm 2 26}{2 ( - 2 )}

Trenne die Lösungen

x_{1} = \frac{- 12 + 2 26}{2 ( - 2 )}, x_{2} = \frac{- 12 - 2 26}{2 ( - 2 )}

x = \frac{- 12 + 2 26}{2 ( - 2 )} : \frac{6 - 26}{2}

x = \frac{- 12 - 2 26}{2 ( - 2 )} : \frac{6 + 26}{2}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{6 - 26}{2}, x = \frac{6 + 26}{2}

x^{2} - \frac{3}{2} x = \frac{7}{16}

1 4^{2} + x^{2} = 5 0^{2}

q u a d r a t i c f or m u l a x^{2} + 5 x + 5 = 0

x^{2} + 64 = 100

7 x^{2} - 4 x + 8 = 0