What are the solutions to the equation 12x^2-5x-7=0 ?

The solutions to the equation 12x^2-5x-7=0 are x=1,x=-7/12

Find the zeros of 12x^2-5x-7=0

The zeros of 12x^2-5x-7=0 are x=1,x=-7/12

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12 x^{2} - 5 x - 7 = 0

x = 1, x = - \frac{7}{12}

Decimal Notation

x = 1, x = - 0.58333 \dots

Solution steps

12 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 7 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 7) = 19

x_{1, 2} = \frac{- ( - 5 ) \pm 19}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 19}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 19}{2 \cdot 12}

x = \frac{- ( - 5 ) + 19}{2 \cdot 12} : 1

x = \frac{- ( - 5 ) - 19}{2 \cdot 12} : - \frac{7}{12}

The solutions to the quadratic equation are:

x = 1, x = - \frac{7}{12}

3 (x - 4) = 2 - 2 x + 7

\frac{2}{- i}

19 = - 8 v - 4 v - 17

34 = 100 t - 16 t^{2}

What are the solutions to the equation 12x^2-5x-7=0 ?
The solutions to the equation 12x^2-5x-7=0 are x=1,x=-7/12
Find the zeros of 12x^2-5x-7=0
The zeros of 12x^2-5x-7=0 are x=1,x=-7/12