faktorisieren 6x^4-11x^3-6x^2+9x-2

Lösung

faktorisieren

6 x^{4} - 11 x^{3} - 6 x^{2} + 9 x - 2

(x + 1) (2 x - 1) (3 x - 1) (x - 2)

Schritte zur Lösung

6 x^{4} - 11 x^{3} - 6 x^{2} + 9 x - 2

Wende den rationalen Nullstellentest an

= (x + 1) \frac{6 x ^{4} - 11 x ^{3} - 6 x ^{2} + 9 x - 2}{x + 1}

\frac{6 x ^{4} - 11 x ^{3} - 6 x ^{2} + 9 x - 2}{x + 1} = 6 x^{3} - 17 x^{2} + 11 x - 2

= (x + 1) (6 x^{3} - 17 x^{2} + 11 x - 2)

Faktorisiere

6 x^{3} - 17 x^{2} + 11 x - 2 : (2 x - 1) (3 x - 1) (x - 2)

= (x + 1) (2 x - 1) (3 x - 1) (x - 2)

s im pl i f y \frac{( 7 x ^{2} \cdot x \cdot ( x y ) ^{6} )}{( x ^{9} \cdot y ^{3} )}

f (t) = cos (t) (3)^{\frac{1}{2}}

s im pl i f y \frac{( 2 n - 3 ) !}{( 2 n - 1 ) !}

s im pl i f y x^{3} n + x^{- 3} n

e x p an d (x^{2} - 4 y^{2})^{3}