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Frequently Asked Questions (FAQ)
What are the solutions to the equation 8x^2-x+4=0 ?
- The solutions to the equation 8x^2-x+4=0 are x= 1/16+i(sqrt(127))/(16),x= 1/16-i(sqrt(127))/(16)
Find the zeros of 8x^2-x+4=0
- The zeros of 8x^2-x+4=0 are x= 1/16+i(sqrt(127))/(16),x= 1/16-i(sqrt(127))/(16)